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If `5x^(3) +Mx+ N, M,N in R` is divisible by `x^(2) + x+1`, then the value of `M +N ` isA. 5B. 4C. `-4`D. `-5` |
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Answer» Correct Answer - D Let `f(x)=5x^(2)+Mx+N`. Also, `x^(2)+x+1=(x-omega)(x-omega^(2))` It is given that `f(x)` is divisible by `x^(2)+x+1`. `therefore f(omega)=5+Momega+N=0` and `f(omega^(2))=5+Momega^(2)+N=0` So, `M =0 and N=-5` `therefore M+N =-5` |
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