1.

If 6.022xx10^(20) molecules are present in 100 mL urea solution, then find out the concentration of urea solution.

Answer»

0.01 M
0.001 M
0.2 M
0.1 M

Solution :Mole `= 10^(-3)`
`6.022xx10^(23)` molecule urea = 1 mole urea
`6.022xx10^(20)` molecule urea = (?)
`THEREFORE M=(10^(-3))/(0.1("liter"))=0.01M`


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