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If 6.3 g of NaHCO_(3) are added to 15.0 g of CH_(3)COOH solution, the residue is found to weigh 18.0 g. The mass of CO_(2) released in the reaction is |
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Answer» 9.3 g Mass of reactants = Mass of PRODUCTS `6.3 g + 15.0 g= 18.0 g+` Mass of `CO_(2)` Mass of `CO_(2) = 6.3g + 15.0g - 18.0 g = 3.3 g` |
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