1.

If 60% of a first order reaction was completed in 60 minutes , 50% of the same reaction would be completed in approximately

Answer»

50 MINUTES
45 minutes
60 minutes
40 minutes

Solution :`K = (2.303)/(60) "LOG" (100)/(40) implies 0.152`
`k = (0.693)/(T_(1//2)) T_(1//2) = (0.693)/(0.152) = 45.37` min .


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