1.

If 61.25 gm of K ClO_(3) reacts with excess of red phosphorus, what mass of tetraphosphorous dioxide (P_(4) O_(10)) would be produced. K ClO_(3) (s) + P_(4) (s) rarr P_(4) O_(10) (s) + K Cl (s)

Answer»

`142 gm`
`426 gm`
`14.2 gm`
`32.6 gm`

Solution :`10 KClO_(3) (s) + 3P_(4) (s) rarr 3 P_(4)O_(10) (s) + 10 KCl (s)`
`61.25 gm`
`N = (61.25)/(122.5)`
`{:(n = (1)/(2) " mole" ,n = (3)/(10) xx (1)/(2),),(,n = (3)/(20) " mole",):}`
mass of `P_(4)O_(10) = (3)/(20) (3 1 xx 4 + 10 xx 16)`
`= (3)/(20) (284)`
`= 14.2 xx 3`
`= 32.6 gm`


Discussion

No Comment Found

Related InterviewSolutions