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If ` [(7, -6), (8, -7)]^2008 = [(7, -6), (8, -7)]^2010` then `[(7, -6), (8, -7)]^2009` isA. `({:(7, -6), (8, -7):})^(2008) + ({:(7, -6), (8, -7):})^(2010)`B. `(1)/(2) [({:(7, -6), (8, -7):})^(2010) -({:(7, -6), (8, -7):})^(2008)]`C. `({:(1, 0), (0, 1):})`D. `({:(7, -6), (8, -7):})` |
Answer» Correct Answer - D (i) Let `A =({:(7, -6), (8, -7):})` (ii) Calculate `A^(2)` |
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