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If 772 mL of SO_(2) gas at STP is adsorbed on 2 g of charcoal at an equlibrium pressure of 16 atmospheres and the value of the constant 'k' in the Freundlich equation is 0.48. the value of the constant 'n' will be

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Solution :Molar mass of `SO_(2)=64 G mol^(-1)`
Moar volume at `STP=22400mL`
`THEREFORE` ML of `SO_(2)` at STP well have mass
`=(64)/(22400)xx772=1.92g`
`therefore x/m=(1.92)/(2)=0.96`
But `x/m=kP^(1//n)`
`therefore 0.96 =0.48 xx(16)^(1//n) or 2=(16)^(1//n)`
`therefore n=4.`


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