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If `(7x+4y) : (7x-4y) ::(7p+4q):(7p-4q)`, there show that x , y, p and q are in proportion. |
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Answer» Given , `(7x+4y)/(7x-4y) = (7p+4q)/(7p-4q)` Using componendo- dividendo rule, `((7x|4y)|(7x 4y))/((7x+4y)-(7x-4y))=((7p|4q)|(7p 4q))/((7p+4q)-(7p-4q))rArr(14x)/(8y)rArrx/y = p/q` `:.` x, y, p, and q are in proportion. |
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