1.

If `8 cos^2 theta+8 sec^2 theta=65` and `0^@` < `theta`

Answer» `8cos^theta+8sec^2theta=65`
`Let cos^2theta=t`
`8t+8/t=65`
`8t^2-65t+8=0`
`8t(t-8)-1(t-8)=0`
`(8t-1)(t-8)`
`t=1/8,8`
`cos^2theta=1/8`
`costheta=1/(2sqrt2)`
`4cos2theta=4(2cos^2theta-1)`
`=4(2*1/8-1)`
`=-3`.


Discussion

No Comment Found