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If `a_(0)` is the Bohr radius, the radius of then `n=2` electronic orbit in triply ionized beryllium isA. `4a_(0)`B. `a_(0)`C. `a_(0)//4`D. `a_(0)//16` |
Answer» Correct Answer - B `r=a_(0)=(n^(2))/(Z)=a_(0).(2^(2))/(4)=a_(0)` |
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