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If `{:A=[(0,1,-1),(2,1,3),(3,2,1)]:}` then `(A(adj A)A^(-1))A=`A. `2{:[(3,0,0),(0,3,0),(0,0,3)]:}`B. `{:[(-6,0,0),(0,-6,0),(0,0,-6)]:}`C. `{:[(0,1//6,-1//6),(2//6,1//6,3//6),(3//6,2//6,1//6)]:}`D. none of these |
Answer» Correct Answer - A We have, `{:absA=[(0,1,-1),(2,1,3),(3,2,1)]:}=0+7-1=6` `:. (A(adj A)A^(-1))A=(A(adjA))(A^(-1)A)` `rArr(A(adj A)A^(-1))A=(absAI)I` `rArr(A(adj A)A^(-1))A=absAI={:[(6,0,0),(0,6,0),(0,0,6)]=2[(3,0,0),(0,3,0),(0,0,3)]:}` Hence, option (a) is correct. |
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