1.

If `{:A=[(0,1,-1),(2,1,3),(3,2,1)]:}` then `(A(adj A)A^(-1))A=`A. `2{:[(3,0,0),(0,3,0),(0,0,3)]:}`B. `{:[(-6,0,0),(0,-6,0),(0,0,-6)]:}`C. `{:[(0,1//6,-1//6),(2//6,1//6,3//6),(3//6,2//6,1//6)]:}`D. none of these

Answer» Correct Answer - A
We have,
`{:absA=[(0,1,-1),(2,1,3),(3,2,1)]:}=0+7-1=6`
`:. (A(adj A)A^(-1))A=(A(adjA))(A^(-1)A)`
`rArr(A(adj A)A^(-1))A=(absAI)I`
`rArr(A(adj A)A^(-1))A=absAI={:[(6,0,0),(0,6,0),(0,0,6)]=2[(3,0,0),(0,3,0),(0,0,3)]:}`
Hence, option (a) is correct.


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