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If `A=[(1,2,-1),(-1,1,2),(2,-1,1)]`, then det (adj(adj A) isA. `14^4`B. `14^3`C. `14^2`D. 14 |
Answer» Correct Answer - A We know that for a square matrix of order n adj (adjA)`=abs(A)^(n-2)A," if " absA ne 0`. `rArr "det (adj(adj A))" abs(abs(A)^(n-2)A)` `rArr "det (adj(adj A)) "(abs(A)^(n-2))^nabsA` `rArr " det(adj)(adj A))" =abs(A)^(n^2-2n+1)` Here, n=3 and and `absA=14`. `:. " det(adj(adj A))"=14^4` |
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