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If `A={1,2}," find "AxxAxxA.` |
Answer» `AxxA={1,2}xx{1,2}={(1,1),(1,2),(2,1),(2,2)}.` `:." "AxxAxxA=(AxxA)xxA` `={(1,1),(1,2),(2,1),(2,2)}xx{1,2}` `={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(2,1,2),(2,2,1),(2,2,2)}.` |
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