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If A(1,2),O(0,0),C(a,b)are collinear then |
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Answer» -step EXPLANATION:Given,A(1,2),O(0,0),C(a,b)Now Consider,A(1,2),O(0,0)x1 = 1, x2 = 0; y1 = 2, y2 = 0W.K.T,___________________________________The distance between 2 points = √(x2-x1)^2 + (y2-y1)^2___________________________________= √(0-1)^2 + (0-2)^2= √(-1)^2 + (-2)^2= √(1) + (4)= √5:. AO = √5Now Consider,O(0,0),C(a,b)x1 = 0, x2 = a; y1 = 0, y2 = bW.K.T,___________________________________The distance between 2 points = √(x2-x1)^2 + (y2-y1)^2___________________________________= √(a-0)^2 + (b-0)^2= √(a)^2 + (b)^2= √(a) + (b)= √ab:.OC = √abNow Consider,A(1,2),C(a,b)x1 = 1, x2 = a; y1 = 2, y2 = bW.K.T,___________________________________The distance between 2 points = √(x2-x1)^2 + (y2-y1)^2___________________________________= √(a-1)^2 + (b-2)^2= √(a-1) + (b-4)= √(ab) + (-5)= √(ab) - (5):.AC = √(ab) - (5). |
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