If a=(2^2*3^3*5^4)and b=(2^3*3^2*5),then find HCF(a,b)

1.	If a=(2^23^35^4)and b=(2^33^25),then find HCF(a,b)
Answer» It is given that: a = (2² × 3³ × 5⁴ ) and b = (2³× 3² × 5) ∴HCF (a,b) = Product of smallest power of each common prime factor in the numbers. = 2² × 3² × 5 = 180 Step-by-step explanation: The given numbers are $2^2\times 3^3\times 5^4$ $b=2^3\times 3^2\times 5$ Highest Common Factor of a and b : It is a largest positive integer that divides both a and b. $2^2 \times 3^2 \times 5$

If a=(2^23^35^4)and b=(2^33^25),then find HCF(a,b)

Answer»

It is given that:

a = (2² × 3³ × 5⁴ ) and b = (2³× 3² × 5)

∴HCF (a,b) = Product of smallest power of each common prime factor in the numbers.

= 2² × 3² × 5

= 180

Step-by-step explanation:

The given numbers are

$2^2\times 3^3\times 5^4$

$b=2^3\times 3^2\times 5$

Highest Common Factor of a and b :

It is a largest positive integer that divides both a and b.

$2^2 \times 3^2 \times 5$