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if `A=[[2,-3],[-4,1]]` then `(3A^2+12A)=?`A. `[[72,-63],[-84,51]]`B. `[[72,-84],[-63,51]]`C. `[[51,63],[84,72]]`D. `[[51,84],[63,72]]`

Answer» Correct Answer - C
`because A^(2) = [[2,-3],[-4,1]][[2, -3],[-4, 1]]= [[16,-9],[-12,13]]`


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