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If a = 2+ √ 3 then find the value of a²+1/a²​

Answer» <html><body><p><strong><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>:</strong></p><p></p><p><strong>a^2 = (2+root3)(2+root3)</strong></p><p>       = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> + <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> + <img align="absmiddle" alt="4\sqrt{3}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D" title="4\sqrt{3}"/></p><p>       = <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> + <img align="absmiddle" alt="4\sqrt{3}" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D" title="4\sqrt{3}"/></p><p><strong>1/a^2 = 7 - </strong><img align="absmiddle" alt="4\sqrt{3}" class="latex-formula" id="TexFormula3" src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D" title="4\sqrt{3}"/> ( By Rationalising )</p><p></p><p>Hence 7 + <img align="absmiddle" alt="4\sqrt{3}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D" title="4\sqrt{3}"/> + 7<strong> - </strong><img align="absmiddle" alt="4\sqrt{3}" class="latex-formula" id="TexFormula5" src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D" title="4\sqrt{3}"/> = 7 + <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a></p><p></p><h2>= <strong>7</strong></h2><h2>ez boi</h2></body></html>


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