1.

If `a^2+b^2=1` then `(1+b+i a)/(1+b-i a)=`A. 1B. 2C. 5D. 8

Answer» Correct Answer - C
Given that `a^(2) +b^(2)=1` Therefore,
`(1+b + ia)/(1+b -ia) =((1+b+ia)(a+b+ia))/((1+ b-ia)(1+b+ia))`
`= ((1+b)^(2) -a^(2)+2ia(1+b))/(1+ b^(2)+2b+a^(2))`
`= ((1-a^(2)) + 2b b^(2) + 2ia(1+b))/(2(l+b))`
`= (2b^(2) + 2b + 2ia(1+b))/(2(1+b))= b + ia`


Discussion

No Comment Found

Related InterviewSolutions