If a=2 b=-3 z=5 then solve 3a2-4b2+5z2 – InterviewSolution

1.

If a=2 b=-3 z=5 then solve 3a2-4b2+5z2

Answer»

Answer:

101 is the answer

Step-by-step explanation:

3a² -4b² +5z²

put a = 2, b = -3 and z = 5

3(2)² - 4(-3)² + 5(5)²

= 3(4) - 4(9) + 5(25)

= 12 - 36 + 125

= 101

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