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If a `298K` the bond energies of `C-H,C-C,C=C` and `H-H` bonds are respectivly `414, 347, 615KJmol^(-1)` , the vlaue of enthalpy change for the reaction `H_(2)C=CH_(2)(g)+H_(2)(g)+H_(2)(g)rarrH_(3)C-CH_(3)(g)` at `298K` will beA. `+250KJ`B. `-250KJ`C. `+125KJ`D. `-125KJ` |
Answer» Correct Answer - B `CH_(2)=CH_(2)(g)+H_(2)(g)rarrH_(3)C-CH_(3)(g)` `4E_(C-H)implies 414xx4=16566E_(C-H) implies 414xx6=2484` `1E_(C=C) implies 615xx1=61E_(C-C) implies 347xx1=347` `1E_(H-H) implies 435xx1=435` `4DeltaH_(C-H)+DeltaH_(C=C)+DeltaH_(H-H)=2706rarr` `6DeltaH_(C-H)+DeltaH_(C-C)=2831` `DeltaH=2706-2831=-125KJ` |
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