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InterviewSolution
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If a `298K` the bond energies of `C-H,C-C,C=C` and `H-H` bonds are respectivly `414, 347, 615KJmol^(-1)` , the vlaue of enthalpy change for the reaction `H_(2)C=CH_(2)(g)+H_(2)(g)+H_(2)(g)rarrH_(3)C-CH_(3)(g)` at `298K` will beA. `+250 kJ`B. `-250 kJ`C. `+125 kJ`D. `-125 kJ` |
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Answer» Correct Answer - D `DeltaH=sumB.E."of reactants"-sumB.E."of products"` `=B.E.(C=C)+4xxB.E.(C-H)+B.E.(H-H)-B.E.(C-C)-6xxB.E.(C-H)` `=B.E.(C=C)+B.E.(H-H)-B.E.(C-C)-2xxB.E.(C-H)` `=615+435-347-2xx414=1050-1175` `=-125 kJ` |
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