1.

If `(A)=3/10,P(B)=2/5 and P(AcupB)=3/5` then P(B/A)+P(A/B) equals toA. `1/4`B. `1/3`C. `5/12`D. `7/12`

Answer» Here, `P(A)=3/10,P(B)=2/5andP(AcupB)=3/5`
`P(B//A)+P(A//B)=(P(BcapA))/(P(A))+(P(AcapB))/(P(B))`
`=(P(A)+P(B)-P(AcupB))/(P(A))`+`=(P(A)+P(B)-P(AcupB))/(P(B))`
`[{:(becauseP(AcupB)=P(A)+P(B)-P(AcapB)),("i.e.,"P(AcapB)=P(A)+P(B)-P(AcupB)):}]`
`=(3/10+2/5-3/5)/(3/10)+(3/10+2/5-3/5)/(2/5)`
`=(1/10)/(3/10)+(1/10)/(2/5)=1/3+1/4=7/12`


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