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If `a^3+b^3+6a b c=8c^3&omega`is a cube root of unity then:`a , b , c`are in `AdotPdot`(b) `a , b , c ,`are in `HdotPdot``a+bomega-2comega^2=0``a+bomega^2-2comega=0`A. `a,c,b` are in A.PB. a,c,b are in H.PC. `a+bomega - 2comega^(2) = 0`D. `a+ bomega^(2) -2comega = 0`

Answer» Correct Answer - A::C::D
We have `a^(3) + b^(3) - 8c^(3) + 6abc = 0`
`rArr a^(3) + b^(3) + (-2c)^(3) - 3ab(-2c) = 0`
`rArr (a + b- 2c) (a+bomega - 2comega^(2)) (a+ boemga^(2)-2comega) =0`


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