1.

If A(-4, 8), B(-3, -4), C(0, -5) and D(5, 6) are vertices of quadrilateral then find its area.

Answer»

Let A(x1, y1) = (-4, 8), B(x2, y2) = (-3, -4), C(x3, y3) = (0, –5) and D(x4, y4) = (5, 6) be the vertices of quadrilateral ABCD.

Area of quad. ABCD = \(\frac{1}{2}\) |{(x1 y2 – x2 y1) + (x2y3 – x3y2) + (x3y4 – x4y3) + (x4y1 – x1y4)}|

\(\frac{1}{2}\) |{(-4 × (-4) – (-3) × 8) + (-3 × (–5) – 0 × (-4)) + (0 × 6 – 5 × (–5)) + (5 × 8 – (-4) × 6)}|

\(\frac{1}{2}\) |{(16 + 24) + (15 + 0) + (0 + 25) + (40 + 24)}|

\(\frac{1}{2}\) |{40 + 15 + 25 + 64}| 

\(\frac{1}{2}\)x 144 

= 72 sq. units.



Discussion

No Comment Found

Related InterviewSolutions