1.

Find the points on the x–axis which are at a distance of 2√5 from the point (7, –4). How many such points are there?

Answer»

Let coordinates of the point=(x, 0)(given that the point lies on x axis)

x1=7. y1=-4

x2=x. y2=0

Distance =√(x2-x1)2+ (y2-y1)2

According to the question,

2√5=√(x-7)2+ (0-(-4))2

Squaring L.H.S and R.H.S

20=x2+49-14x+16

20=x2+65-14x

0=x2-14x+45

0=x2-9x-5x+45

0=x(x-9)-5(x-9)

0=(x-9) (x-5)

x-9 =0. x-5= 0

x=9 or x=5

Therefore, coordinates of points…..(9,0)or(5,0)



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