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Find the points on the x–axis which are at a distance of 2√5 from the point (7, –4). How many such points are there? |
Answer» Let coordinates of the point=(x, 0)(given that the point lies on x axis) x1=7. y1=-4 x2=x. y2=0 Distance =√(x2-x1)2+ (y2-y1)2 According to the question, 2√5=√(x-7)2+ (0-(-4))2 Squaring L.H.S and R.H.S 20=x2+49-14x+16 20=x2+65-14x 0=x2-14x+45 0=x2-9x-5x+45 0=x(x-9)-5(x-9) 0=(x-9) (x-5) x-9 =0. x-5= 0 x=9 or x=5 Therefore, coordinates of points…..(9,0)or(5,0) |
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