1.

The distance between the points (0, 5) and (–5, 0) is(A) 5 (B) 5√2 (C) 2√5 (D) 10

Answer»

(B) 52

Distance formula: d2 = (x2 – x1)2 + (y2 – y1)2

According to the question,

We have;

x1 = 0, x2 = – 5

y2 = 5, y2 = 0

d2 = (( – 5) – 0)2 + (0 – 5)2

d= √(-5-0)2+ (0-5)2

d= √((-5)2+ (-5)2)

d = √(25 + 25)

d= √50= 5√2

So the distance between (0, 5) and ( – 5, 0) = 5√ 2



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