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If a = 5 ,b = 6 and c = 10 , find the value of: a+b_c-a |
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Answer» (a+b)=6K (b+c)=7k (c+a)=8k Now, we get ADDITION of LHS & RHS 2a+2b+2c=21k 2(a+b+c)=21k 2(14)=21k —————- [given - (a+b+c)=14] 28=21k k=28/21=4/3 ———————(1) Since, a+b+c=14 c=14-(a+b) we have, a+b=6k a+b=6(4/3) ——————-from 1 a+b=8 now, c=14-(a+b) c=14–8 c=6 Step-by-step EXPLANATION: UR answer mate mark as brainlist plz❤✔ |
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