1.

If a 50g block of solid marble (specifc heat=0.9kJ//kg""^(@)C), originally at 20^(@)C, absorbs 100J ofheat, which one of the following best approximates the temperature increases of the marble block?

Answer»

`1^(@)C`
`2^(@)C`
`4^(@)C`
`10^(@)C`

SOLUTION :We use the EQUATION `q=mcDeltaT` to FIND `DeltaT`.
`DeltaT=(q)/(mc)=(0.1kJ)/((0.05kg)(0.9kG//kg*""^(@)C))=(2)/(0.9)=2^(@)C`.


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