If A = 5i + 6j + 9k; Find the unit vector of A.

1.	If A = 5i + 6j + 9k; Find the unit vector of A.
Answer» Unit vector \(\vec A=\frac{\vec A}{\|\vec A\|}\) We have A = 5i + 6j + 9k \(\|\vec A\|=\sqrt{5^2+6^2+9^2}\) =\(\sqrt{142}\) Unit vector \(\vec A=\frac{5\hat i+6\hat j+9\hat k}{\sqrt{142}}\) \(=\frac{5}{\sqrt{142}}\hat i+\frac{6}{\sqrt{142}}\hat j+\frac{9}{\sqrt{142}}\hat k\)

Answer»

Unit vector \(\vec A=\frac{\vec A}{|\vec A|}\)

We have

A = 5i + 6j + 9k

\(|\vec A|=\sqrt{5^2+6^2+9^2}\)

=\(\sqrt{142}\)

Unit vector \(\vec A=\frac{5\hat i+6\hat j+9\hat k}{\sqrt{142}}\)

\(=\frac{5}{\sqrt{142}}\hat i+\frac{6}{\sqrt{142}}\hat j+\frac{9}{\sqrt{142}}\hat k\)

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If A = 5i + 6j + 9k; Find the unit vector of A.

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