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If `A={:((a-a,b-b)):}" then "((1)/(ab))A=`A. `((1)/(b)+(1)/(b) (1)/(a)-(1)/(a))`B. `((1)/(a)-(1)/(a)(1)/(b)-(1)/(b))`C. `((1)/(b)-(1)/(b)(1)/(a)-(1)/(a))`D. `(a^(2)b" "-a^(2)b" "b^(2)a" "-b^(2)a)` |
Answer» Correct Answer - C Apply scalar product of a matrix. |
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