1.

If `{:A=[(a,b),(c,d)]:}` such that `ad - bc ne 0`, then `A^(-1)`, isA. `1/(ad-bc){:[(a,-b),(-c,a)]:}`B. `1/(ad-bc){:[(a,-b),(-c,a)]:}`C. `{:[(d,b),(-c,a)]:}`D. none of these

Answer» Correct Answer - A
We have, `absA=ad-bcne0`
Cofactor of `a_11=d," Cofactor of "a_12=-c`
Cofactor of `a_21=-b," Cofactor of "a_22 =a`
`:. A^(-1) =1/absAadjA =1/(ad-bc){:[(d,-b),(-c,a)]:}`


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