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If `{:A=alpha[(1,1+i),(1-i,-1)]:}a in R`, is a unitary matrix then `alpha^2` isA. `1/2`B. `1/3`C. `1/4`D. `2/9` |
Answer» Correct Answer - B It is given that A is a unitary matrix. `:. A(overset-A)^T=I` `rArr{:alpha[(1,1+i),(1-i,-1)]alpha[(1,1+i),(1-i,-1)]=[(1,0),(0,1)]:}` `{:alpha^2[(3,0),(0,3)]=[(1,0),(0,1)]:}` `rArr 3alpha^2=1rArr alpha^2=1/3` |
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