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If `A=[alphabetagamma-alpha]`is such that `A^2=I`, then`1+alpha^2+betagamma=0`(b) `1-alpha^2+betagamma=0`(c) `1-alpha^2-betagamma=0`(d) `1+alpha^2-betagamma=0`A. `1+alpha^(2)+betagamma =0`B. `1-alpha^(2) +beta gamma =0`C. `1-alpha^(2)-beta gamma=0`D. `1+alpha^(2)-beta gamma =0` |
Answer» Correct Answer - A `A^(2) =I` `implies [{:(alpha,beta),(gamma,-alpha):}][{:(alpha,beta),(gamma,-alpha):}]=I` `implies[{:(alpha^(2)+betagamma,alphabeta-betaalpha),(gammaalpha -alphagamma,betagamma +alpha^(2)):}]=I` `implies [{:(alpha^(2) +beta gamma ,0),(0, alpha^(2) +betagamma ):}]=[{:(1,0),(0,1):}]` `alpha^(2) +beta gamma =1 implies 1-alpha^(2) -betagamma =0` |
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