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If A and B are mutually exclusive events of an experiment. If P (not A) = 0.65, P(A ∪ B) = 0.65 and P(B) = P, then find the value of P. |
Answer» Given, P(not A) = 0.65 ⇒ 1 – P(A) = 0.65 ⇒ P(A) = 0.35 P(A ∪ B) = 0.65, p(B) =p . Since A, B are mutually exclusive, so– P(A ∪ B) = P(A) + P(B) ⇒ 0.65 = 0.35 + P ⇒ P = 0.30 |
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