1.

If A and B are mutually exclusive events of an experiment. If P (not A) = 0.65, P(A ∪ B) = 0.65 and P(B) = P, then find the value of P.

Answer»

Given, 

P(not A) = 0.65 

⇒ 1 – P(A) = 0.65 

⇒ P(A) = 0.35 

P(A ∪ B) = 0.65, p(B) =p . 

Since A, B are mutually exclusive, so–

 P(A ∪ B) = P(A) + P(B) 

⇒ 0.65 = 0.35 + P 

⇒ P = 0.30



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