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If A and B are symmetric matrices of same order, prove that (i) AB + BA is a symmetric matrix. (ii) AB – BA is a skew-symmetric matrix. |
Answer» Given A and B are symmetric matrices ⇒ – AT = A and BT = B (i) To prove AB + BA is a symmetric matrix. Proof: Now (AB + BA)T = (AB)T + (BA)T = BT AT + AT BT = BA + AB = AB + BA i.e. (AB + BA)T = AB + BA ⇒ (AB + BA) is a symmetric matrix. (ii) To prove AB – BA is a skew symmetric matrix. Proof: (AB – BA)T = (AB)T – (BA)T = BT AT – AT BT = BA – AB i.e. (AB – BA)T = – (AB – BA) ⇒ AB – BA is a skew symmetric matrix. |
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