If A and B are the 2 independent events, have P(A) = 0.6 and P(B) = 0.

1.	If A and B are the 2 independent events, have P(A) = 0.6 and P(B) = 0.2,then what will be P((A∪B)')?1. 0.562. 0.323. 0.684. 0.44
Answer» Correct Answer - Option 2 : 0.32 Concept: For any two independent events A and B, if P(A) and P(B) are their probability of occurring then: P(A ∩ B) = P(A) × P(B) P(A ∪ B) = P(A) + P(B) - P(A ∩ B) P(A') = 1 - P(A) P(B') = 1 - P(B) Calculation: Given P(A) = 0.6 and P(B) = 0.2 P(A ∩ B) = P(A) × P(B) ⇒ P(A ∩ B) = 0.6 × 0.2 = 0.12 P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ⇒ P(A ∪ B) = 0.6 + 0.2 - 0.12 ⇒ P(A ∪ B) = 0.68 P((A ∪ B)') = 1 - P(A ∪ B) ⇒ P((A ∪ B)') = 1 - 0.68 ⇒ P((A ∪ B)') = 0.32

If A and B are the 2 independent events, have P(A) = 0.6 and P(B) = 0.2,then what will be P((A∪B)')?1. 0.562. 0.323. 0.684. 0.44

Answer» Correct Answer - Option 2 : 0.32

Concept:

For any two independent events A and B, if P(A) and P(B) are their probability of occurring then:

P(A ∩ B) = P(A) × P(B)
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
P(A') = 1 - P(A)
P(B') = 1 - P(B)

Calculation:

Given P(A) = 0.6 and P(B) = 0.2

P(A ∩ B) = P(A) × P(B)

⇒ P(A ∩ B) = 0.6 × 0.2 = 0.12

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

⇒ P(A ∪ B) = 0.6 + 0.2 - 0.12

⇒ P(A ∪ B) = 0.68

P((A ∪ B)') = 1 - P(A ∪ B)

⇒ P((A ∪ B)') = 1 - 0.68

⇒ P((A ∪ B)') = 0.32

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If A and B are the 2 independent events, have P(A) = 0.6 and P(B) = 0.2,then what will be P((A∪B)')?1. 0.562. 0.323. 0.684. 0.44

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