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If a and b are the roots of the quadratic equation x²+px+12=0 with the condition a-b=1, then what is the value of p? |
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Answer» Sum of ROOTS = a + B = -p.Product of roots = ab = 12.(a - b)^2 = (a + b)^2 - 4(ab) = p^2 - 48 = 1. ==>*** p = ±7.***Case 1: X^2 + 7x + 12 = (x+4)(x+3)=0. x = -4 or -3.Case 2: x^2 - 7x + 12 = (x -4)(x-3)=0. x = 4 or 3 |
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