If a and b are the zeros of the polynomial x²+7x+7 find the value of

1.	If a and b are the zeros of the polynomial x²+7x+7 find the value of alhpa-¹ and beta-¹-2alhpa beta
Answer» Given polynomial is x² + 7x + 3 Given α and β are ZEROES of this polynomials then α + β = -7 α × β = 3 Now (α - β)² = (α + β)² - 4α β = (-7)2 - 4(-7)3 = 49 + 84 = 133 => α - β = √133 So α - β = √133

If a and b are the zeros of the polynomial x²+7x+7 find the value of alhpa-¹ and beta-¹-2alhpa beta

Answer»

Given polynomial is

x² + 7x + 3

Given α and β are ZEROES of this polynomials then

α + β = -7

α × β = 3

Now

(α - β)² = (α + β)² - 4α β

= (-7)2 - 4(-7)3

= 49 + 84

= 133

=> α - β = √133

So α - β = √133