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If α and β are the zeros of the polynomials x2-7x+6 then (α+β)2 = |
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Answer» x²-7x+6=0 x²-6x-x+6=0 x(x-6)-1(x-6)=0 (x-1)(x-6)=0 so ROOTS = 1,6 so (1+6)² =49 |
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