If A and B are two events such that `AsubB`and `P(B)!=0,`them which of the following is correct?(A) `P(A | B) =(P(B))/(P(A)` (B) `P(A|B)ltP(A)` (C) `P(A|B)geP(B)` (D) none of these

If A and B are two events such that `AsubB`and `P(B)!=0,`them which of

1.	If A and B are two events such that `AsubB`and `P(B)!=0,`them which of the following is correct?(A) `P(A \| B) =(P(B))/(P(A)` (B) `P(A\|B)ltP(A)` (C) `P(A\|B)geP(B)` (D) none of these
Answer» As, we are given that `A sub B`, it means `P(AnnB) = P(A)` Then, `P(A\|B) = (P(AnnB))/(P(B)) = (P(A))/(P(B))` so, option A is incorect. Now, we are given that, `P(B)!=0` means `P(B)<=1` If `P(B)<=1`, then it implies,`P(A\|B)>=P(A)` which is the correct option.

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If A and B are two events such that `AsubB`and `P(B)!=0,`them which of the following is correct?(A) `P(A | B) =(P(B))/(P(A)` (B) `P(A|B)ltP(A)` (C) `P(A|B)geP(B)` (D) none of these

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