If A and B are two events, the probability that exactly one of them occurs is given byA. `P(A) + P(B) - 2P(A nn B)`B. `P(A nn barB) + P(barA nn B)`C. `P(A uu B) - P(A nn B)`D. `P(barA) + P(barB) - 2P(barA nn barB)`

If A and B are two events, the probability that exactly one of them oc

1.	If A and B are two events, the probability that exactly one of them occurs is given byA. `P(A) + P(B) - 2P(A nn B)`B. `P(A nn barB) + P(barA nn B)`C. `P(A uu B) - P(A nn B)`D. `P(barA) + P(barB) - 2P(barA nn barB)`
Answer» Correct Answer - A::B::C::D We have, P(exactly one of A, B occurs) `= P [(A nn barB) uu (barA nn B)]` `=P(A nn barB) + P(barA nn B)` `=P(A) - P(A nn B) + P(B) - P(A nn B)` `=P(A) + P(B) - 2P(A nn B)` `=P(A uu B) - P(A nn B)` Also, P(exactly one of A, B occurs) `=[1 - P(barA nn barB)] - [1 - P(barA uu barB)]` `=P(barAuubarB) - P(barA nn barB) = P(barA) + P(barB) - 2P(barA nn barB)`

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If A and B are two events, the probability that exactly one of them occurs is given byA. `P(A) + P(B) - 2P(A nn B)`B. `P(A nn barB) + P(barA nn B)`C. `P(A uu B) - P(A nn B)`D. `P(barA) + P(barB) - 2P(barA nn barB)`

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