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If A and B are two mutually exclusive events such that P(A) = (1/2) and P(B) = (1/3), find P(A or B). |
Answer» P(A) = 1/2, P(B) = 1/3 We know, P(A or B) = P(A) + P(B) – P(A and B) For mutually exclusive events A and B, P(A and B) = 0 P(A or B) = 1/2 + 1/3 – 0 P(A or B) = 5/6 Ans.5/6........... |
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