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If A and B are two sets such that n (A ∪ B) = 50, n (A) = 28 and n (B) = 32, find n (A ∩ B). |
Answer» Here, we have, n (A ∪ B) = 50 n (A) = 28 n (B) = 32 As we know that, n (A ∪ B) = n (A) + n (B) – n (A ∩ B) On substituting the values we get 50 = 28 + 32 – n (A ∩ B) 50 = 60 – n (A ∩ B) –10 = – n (A ∩ B) ∴ n (A ∩ B) = 10 |
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