1.

The solution of `8x = 6 (mod 14)` isA. [8],[6]B. [8],[14]C. [6],[13]D. [8],[14],[16]

Answer» Correct Answer - C
`lambda=(8x-6)/(14), "where "lambda in I_(+)`
`therefore 8x=14lambda+6impliesx=(14lambda+6)/(8)`
`implies x=(7lambda+3)/(4)=lambda+(3)/(4)(lambda+1),"where "lambda in I` and here greatest common divisor of 8 and 14 is 2, so there are two required solutions. for `lambda = 3 and lambda = 7, x = 6, 13` or x = [6][13]


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