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The solution of `8x = 6 (mod 14)` isA. [8],[6]B. [8],[14]C. [6],[13]D. [8],[14],[16] |
Answer» Correct Answer - C `lambda=(8x-6)/(14), "where "lambda in I_(+)` `therefore 8x=14lambda+6impliesx=(14lambda+6)/(8)` `implies x=(7lambda+3)/(4)=lambda+(3)/(4)(lambda+1),"where "lambda in I` and here greatest common divisor of 8 and 14 is 2, so there are two required solutions. for `lambda = 3 and lambda = 7, x = 6, 13` or x = [6][13] |
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