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If `{:[(a,b^3),(2,0)]=[(1,8),(2,0)]," then " [(a,b),(2,0)]_(-1)^1:}=`A. `{:[(0,-2),(-2,1)]:}`B. `{:[(1,0),(0,1)]:}`C. `{:[(0,-8),(-2,1)]:}`D. `{:[(0,1//2),(1//2,-1//4)]:}` |
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Answer» Correct Answer - D We have, `{:[(a,b^3),(2,0)]=[(1,8),(2,0)]:}rArr a=1,b^3=8rArra=1,b=2` `:. {:[(a,b),(2,0)]=[(1,2),(2,0)]:}` Hence,`{:[(a,b),(2,0)]^(-1)=-1/4[(0,-2),(-2,1)]=[(0,1//2),(1//2,-1//4)]:}` |
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