1.

If a+b = 4 and ab= -12, find 1) a-b2) a^2 - b^2​

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Answer:

Given,

a+b=3 ,

a-b=2,

(a+b)^2=a^2+b^2+2ab————-(1)

(a-b)^2=a^2–2ab+b^2————(2)

(1)-(2)=>(a+b)^2-(a-b)^2=2(a^2+b^2)

=>(3)^2-(2)2=2(a^2+b^2)

=>6–4=2(a^2+b^2)

=>2=2(a^2+b^2)

the VALUE of 2 (a^2+b^2) is 2


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