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If a, b and c are in H.P., then the value of `((ac+ab-bc)(ab+bc-ac))/(abc)^2` isA. `((a+c)(3a -c))/(4a^2 c^2)`B. `2/(bc)-1/b^2`C. `2/(bc)-1/b^2`D. `((a-c)(3a+c))/(4a^2c^2)` |
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Answer» Correct Answer - A::B `(1/b+1/c-1/a)(1/c+1/a-1b)` `=(1/b+1/c-2/b+1/c)(1/c+1/b-1/c)` Also by eliminating b, we get the given expression `((a+c)(3a-c))/(4a^(2)c^(2))` |
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