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If A,B and C are square matrices of order n and det (A)=2, det(B)=3 and det ©=5, then find the value of 10det `(A^(3)B^(2)C^(-1)).` |
Answer» Given , `|A|=2,|B|=3 and |c|=5.` Now, 10det `(A^(3)B^(2)C^(-1))=10xx|A^(3)B^(2)C^(1)|` `=10xx|A^(3)|xx|B^(2)|xx|C^(-1)|=10xx|A^(3)|xx|B^(2)|xx|C|^(-1)` `=(10xx|A^(3)|xx|B^(2)|)/(|C|)=(10xx2^(3)xx3^(2))/(5)=144` |
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