InterviewSolution
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InterviewSolution
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If `a b+b c+c a=0,`then solve `a(b-2c)x^2+b(c-2a)x+c(a-2b)=0.` |
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Answer» As it is given that`ab + bc + ca = 0`, Putting x =1 in the equation, we get `f(1) = a(b - 2c) + b(c - 2a)+ c(a - 2b)` `= - (ab + bc + ca)` =0 So x = 1 is a root of the equation. Let the other root be `alpha` Now product of the roots is `1xxalpha = (c(a - 2b))/(a(b - 2c))` or `alpha =(c)/(a) ((a - 2b)/(b - 2c))` |
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