If a + b + c = 0, then a2bc + b2ca + c2ab=(a) 0(b) 1(c) −1(d) 3 – InterviewSolution

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1.	If a + b + c = 0, then a2bc + b2ca + c2ab=(a) 0(b) 1(c) −1(d) 3
Answer» If a + b + c = 0, then $\frac{a^{2}}{b c} + \frac{b^{2}}{c a} + \frac{c^{2}}{a b} =$ (a) 0 (b) 1 (c) −1 (d) 3

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